Solve 0.02-0.1x/0.03-2=1-2x/1.5

$$\frac { 0.02 - 0.1 x } { 0.03 } - 2 = \frac { 1 - 2 x } { 1.5 }$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Divide each term of 0.02-0.1x by 0.03 to get \frac{0.02}{0.03}+\frac{-0.1x}{0.03}.

$$\frac{0.02}{0.03}+\frac{-0.1x}{0.03}-2=\frac{1-2x}{1.5}$$

Expand \frac{0.02}{0.03} by multiplying both numerator and the denominator by 100.

$$\frac{2}{3}+\frac{-0.1x}{0.03}-2=\frac{1-2x}{1.5}$$

Divide -0.1x by 0.03 to get -\frac{10}{3}x.

$$\frac{2}{3}-\frac{10}{3}x-2=\frac{1-2x}{1.5}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{2}{3}-\frac{10}{3}x-\frac{6}{3}=\frac{1-2x}{1.5}$$

Since \frac{2}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-6}{3}-\frac{10}{3}x=\frac{1-2x}{1.5}$$

Subtract 6 from 2 to get -4.

$$-\frac{4}{3}-\frac{10}{3}x=\frac{1-2x}{1.5}$$

Divide each term of 1-2x by 1.5 to get \frac{1}{1.5}+\frac{-2x}{1.5}.

$$-\frac{4}{3}-\frac{10}{3}x=\frac{1}{1.5}+\frac{-2x}{1.5}$$

Expand \frac{1}{1.5} by multiplying both numerator and the denominator by 10.

$$-\frac{4}{3}-\frac{10}{3}x=\frac{10}{15}+\frac{-2x}{1.5}$$

Reduce the fraction \frac{10}{15} to lowest terms by extracting and canceling out 5.

$$-\frac{4}{3}-\frac{10}{3}x=\frac{2}{3}+\frac{-2x}{1.5}$$

Divide -2x by 1.5 to get -\frac{4}{3}x.

$$-\frac{4}{3}-\frac{10}{3}x=\frac{2}{3}-\frac{4}{3}x$$

Add \frac{4}{3}x to both sides.

$$-\frac{4}{3}-\frac{10}{3}x+\frac{4}{3}x=\frac{2}{3}$$

Combine -\frac{10}{3}x and \frac{4}{3}x to get -2x.

$$-\frac{4}{3}-2x=\frac{2}{3}$$

Add \frac{4}{3} to both sides.

$$-2x=\frac{2}{3}+\frac{4}{3}$$

Since \frac{2}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$-2x=\frac{2+4}{3}$$

Add 2 and 4 to get 6.

$$-2x=\frac{6}{3}$$

Divide 6 by 3 to get 2.

$$-2x=2$$

Divide both sides by -2.

$$x=\frac{2}{-2}$$

Divide 2 by -2 to get -1.

$$x=-1$$