Solve 0,013,1-2000^2/9*10^9=

$$\frac { 0,013,1 - 2000 ^ { 2 } } { 9 \cdot 10 ^ { 9 } } =$$

Evaluate

$$-\frac{1}{2250}\approx -0.000444444$$

Solution Steps

Multiply 0 and 0 to get 0.

$$\frac{0\times 13\times 1-2000^{2}}{9\times 10^{9}}$$

Multiply 0 and 13 to get 0.

$$\frac{0\times 1-2000^{2}}{9\times 10^{9}}$$

Multiply 0 and 1 to get 0.

$$\frac{0-2000^{2}}{9\times 10^{9}}$$

Calculate 2000 to the power of 2 and get 4000000.

$$\frac{0-4000000}{9\times 10^{9}}$$

Subtract 4000000 from 0 to get -4000000.

$$\frac{-4000000}{9\times 10^{9}}$$

Calculate 10 to the power of 9 and get 1000000000.

$$\frac{-4000000}{9\times 1000000000}$$

Multiply 9 and 1000000000 to get 9000000000.

$$\frac{-4000000}{9000000000}$$

Reduce the fraction \frac{-4000000}{9000000000} to lowest terms by extracting and canceling out 4000000.

$$-\frac{1}{2250}$$

Factor

$$-\frac{1}{2250} = -0.00044444444444444447$$