Solve -ab^2/2c^2div3a^2b/4cd=

$$\frac { - a b ^ { 2 } } { 2 c ^ { 2 } } \div \frac { 3 a ^ { 2 } b } { 4 c d } =$$

Evaluate

$$-\frac{2bd}{3ac}$$

Short Solution Steps

Divide \frac{\left(-a\right)b^{2}}{2c^{2}} by \frac{3a^{2}b}{4cd} by multiplying \frac{\left(-a\right)b^{2}}{2c^{2}} by the reciprocal of \frac{3a^{2}b}{4cd}.

$$\frac{\left(-a\right)b^{2}\times 4cd}{2c^{2}\times 3a^{2}b}$$

Cancel out 2bc in both numerator and denominator.

$$\frac{2\left(-a\right)bd}{3ca^{2}}$$

Factor the expressions that are not already factored.

$$\frac{-2abd}{3ca^{2}}$$

Cancel out a in both numerator and denominator.

$$\frac{-2bd}{3ac}$$

Differentiate w.r.t. d

$$-\frac{2b}{3ac}$$