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\frac{\left(-8+10i\right)i}{2i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(-8+10i\right)i}{-2}
By definition, i^{2} is -1. Calculate the denominator.
\frac{-8i+10i^{2}}{-2}
Multiply -8+10i times i.
\frac{-8i+10\left(-1\right)}{-2}
By definition, i^{2} is -1.
\frac{-10-8i}{-2}
Do the multiplications in -8i+10\left(-1\right). Reorder the terms.
5+4i
Divide -10-8i by -2 to get 5+4i.
Re(\frac{\left(-8+10i\right)i}{2i^{2}})
Multiply both numerator and denominator of \frac{-8+10i}{2i} by imaginary unit i.
Re(\frac{\left(-8+10i\right)i}{-2})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{-8i+10i^{2}}{-2})
Multiply -8+10i times i.
Re(\frac{-8i+10\left(-1\right)}{-2})
By definition, i^{2} is -1.
Re(\frac{-10-8i}{-2})
Do the multiplications in -8i+10\left(-1\right). Reorder the terms.
Re(5+4i)
Divide -10-8i by -2 to get 5+4i.
5
The real part of 5+4i is 5.