Solve -5/16+7/20+-7/12+-3/10

$$\frac { - 5 } { 16 } + \frac { 7 } { 20 } + \frac { - 7 } { 12 } + \frac { - 3 } { 10 }$$

Evaluate

$$-\frac{203}{240}\approx -0.845833333$$

Solution Steps

Fraction \frac{-5}{16} can be rewritten as -\frac{5}{16} by extracting the negative sign.

$$-\frac{5}{16}+\frac{7}{20}+\frac{-7}{12}+\frac{-3}{10}$$

Least common multiple of 16 and 20 is 80. Convert -\frac{5}{16} and \frac{7}{20} to fractions with denominator 80.

$$-\frac{25}{80}+\frac{28}{80}+\frac{-7}{12}+\frac{-3}{10}$$

Since -\frac{25}{80} and \frac{28}{80} have the same denominator, add them by adding their numerators.

$$\frac{-25+28}{80}+\frac{-7}{12}+\frac{-3}{10}$$

Add -25 and 28 to get 3.

$$\frac{3}{80}+\frac{-7}{12}+\frac{-3}{10}$$

Fraction \frac{-7}{12} can be rewritten as -\frac{7}{12} by extracting the negative sign.

$$\frac{3}{80}-\frac{7}{12}+\frac{-3}{10}$$

Least common multiple of 80 and 12 is 240. Convert \frac{3}{80} and \frac{7}{12} to fractions with denominator 240.

$$\frac{9}{240}-\frac{140}{240}+\frac{-3}{10}$$

Since \frac{9}{240} and \frac{140}{240} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-140}{240}+\frac{-3}{10}$$

Subtract 140 from 9 to get -131.

$$-\frac{131}{240}+\frac{-3}{10}$$

Fraction \frac{-3}{10} can be rewritten as -\frac{3}{10} by extracting the negative sign.

$$-\frac{131}{240}-\frac{3}{10}$$

Least common multiple of 240 and 10 is 240. Convert -\frac{131}{240} and \frac{3}{10} to fractions with denominator 240.

$$-\frac{131}{240}-\frac{72}{240}$$

Since -\frac{131}{240} and \frac{72}{240} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-131-72}{240}$$

Subtract 72 from -131 to get -203.

$$-\frac{203}{240}$$

Factor

$$-\frac{203}{240} = -0.8458333333333333$$