Solve -4/12divfrac{3{4}+5/12*4/3}

$$\frac { - 4 } { 12 \div \frac { 3 } { 4 } + \frac { 5 } { 12 } \times \frac { 4 } { 3 } }$$

Evaluate

$$-\frac{36}{149}\approx -0.241610738$$

Solution Steps

Divide 12 by \frac{3}{4} by multiplying 12 by the reciprocal of \frac{3}{4}.

$$\frac{-4}{12\times \frac{4}{3}+\frac{5}{12}\times \frac{4}{3}}$$

Express 12\times \frac{4}{3} as a single fraction.

$$\frac{-4}{\frac{12\times 4}{3}+\frac{5}{12}\times \frac{4}{3}}$$

Multiply 12 and 4 to get 48.

$$\frac{-4}{\frac{48}{3}+\frac{5}{12}\times \frac{4}{3}}$$

Divide 48 by 3 to get 16.

$$\frac{-4}{16+\frac{5}{12}\times \frac{4}{3}}$$

Multiply \frac{5}{12} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-4}{16+\frac{5\times 4}{12\times 3}}$$

Do the multiplications in the fraction \frac{5\times 4}{12\times 3}.

$$\frac{-4}{16+\frac{20}{36}}$$

Reduce the fraction \frac{20}{36} to lowest terms by extracting and canceling out 4.

$$\frac{-4}{16+\frac{5}{9}}$$

Convert 16 to fraction \frac{144}{9}.

$$\frac{-4}{\frac{144}{9}+\frac{5}{9}}$$

Since \frac{144}{9} and \frac{5}{9} have the same denominator, add them by adding their numerators.

$$\frac{-4}{\frac{144+5}{9}}$$

Add 144 and 5 to get 149.

$$\frac{-4}{\frac{149}{9}}$$

Divide -4 by \frac{149}{9} by multiplying -4 by the reciprocal of \frac{149}{9}.

$$-4\times \frac{9}{149}$$

Express -4\times \frac{9}{149} as a single fraction.

$$\frac{-4\times 9}{149}$$

Multiply -4 and 9 to get -36.

$$\frac{-36}{149}$$

Fraction \frac{-36}{149} can be rewritten as -\frac{36}{149} by extracting the negative sign.

$$-\frac{36}{149}$$

Factor

$$-\frac{36}{149} = -0.24161073825503357$$