Solve -3/4x-6geq6

$$\frac { - 3 } { 4 } x - 6 \geq 6$$

Solve for x

$$x\leq -16$$

Solution Steps

Fraction \frac{-3}{4} can be rewritten as -\frac{3}{4} by extracting the negative sign.

$$-\frac{3}{4}x-6\geq 6$$

Add 6 to both sides.

$$-\frac{3}{4}x\geq 6+6$$

Add 6 and 6 to get 12.

$$-\frac{3}{4}x\geq 12$$

Multiply both sides by -\frac{4}{3}, the reciprocal of -\frac{3}{4}. Since -\frac{3}{4} is negative, the inequality direction is changed.

$$x\leq 12\left(-\frac{4}{3}\right)$$

Express 12\left(-\frac{4}{3}\right) as a single fraction.

$$x\leq \frac{12\left(-4\right)}{3}$$

Multiply 12 and -4 to get -48.

$$x\leq \frac{-48}{3}$$

Divide -48 by 3 to get -16.

$$x\leq -16$$