Solve -3^2+6div2/(4--8)div(-2)^2

$$\frac { - 3 ^ { 2 } + 6 \div 2 } { ( 4 - - 8 ) \div ( - 2 ) ^ { 2 } }$$

Evaluate

$$-2$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\frac{-9+\frac{6}{2}}{\frac{4-\left(-8\right)}{\left(-2\right)^{2}}}$$

Divide 6 by 2 to get 3.

$$\frac{-9+3}{\frac{4-\left(-8\right)}{\left(-2\right)^{2}}}$$

Add -9 and 3 to get -6.

$$\frac{-6}{\frac{4-\left(-8\right)}{\left(-2\right)^{2}}}$$

The opposite of -8 is 8.

$$\frac{-6}{\frac{4+8}{\left(-2\right)^{2}}}$$

Add 4 and 8 to get 12.

$$\frac{-6}{\frac{12}{\left(-2\right)^{2}}}$$

Calculate -2 to the power of 2 and get 4.

$$\frac{-6}{\frac{12}{4}}$$

Divide 12 by 4 to get 3.

$$\frac{-6}{3}$$

Divide -6 by 3 to get -2.

$$-2$$

Factor

$$-2$$