Solve -2,3*18+7*(-2,3)-(-2*3)*20/10*2,3

$$\frac { - 2,3 \cdot 18 + 7 \cdot ( - 2,3 ) - ( - 2 \cdot 3 ) \cdot 20 } { 10 \cdot 2,3 }$$

Evaluate

$$\frac{125}{46}\approx 2,717391304$$

Solution Steps

Multiply -2,3 and 18 to get -41,4.

$$\frac{-41,4+7\left(-2,3\right)-\left(-2\times 3\times 20\right)}{10\times 2,3}$$

Multiply 7 and -2,3 to get -16,1.

$$\frac{-41,4-16,1-\left(-2\times 3\times 20\right)}{10\times 2,3}$$

Subtract 16,1 from -41,4 to get -57,5.

$$\frac{-57,5-\left(-2\times 3\times 20\right)}{10\times 2,3}$$

Multiply -2 and 3 to get -6.

$$\frac{-57,5-\left(-6\times 20\right)}{10\times 2,3}$$

Multiply -6 and 20 to get -120.

$$\frac{-57,5-\left(-120\right)}{10\times 2,3}$$

The opposite of -120 is 120.

$$\frac{-57,5+120}{10\times 2,3}$$

Add -57,5 and 120 to get 62,5.

$$\frac{62,5}{10\times 2,3}$$

Multiply 10 and 2,3 to get 23.

$$\frac{62,5}{23}$$

Expand \frac{62,5}{23} by multiplying both numerator and the denominator by 10.

$$\frac{625}{230}$$

Reduce the fraction \frac{625}{230} to lowest terms by extracting and canceling out 5.

$$\frac{125}{46}$$

Factor

$$\frac{5 ^ {3}}{2 \cdot 23} = 2\frac{33}{46} = 2.717391304347826$$