Solve -2/3x+5=-8/5

$$\frac { - 2 } { 3 } x + 5 = \frac { - 8 } { 5 }$$

Solve for x

$$x = \frac{99}{10} = 9\frac{9}{10} = 9.9$$

Steps for Solving Linear Equation

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$-\frac{2}{3}x+5=\frac{-8}{5}$$

Fraction \frac{-8}{5} can be rewritten as -\frac{8}{5} by extracting the negative sign.

$$-\frac{2}{3}x+5=-\frac{8}{5}$$

Subtract 5 from both sides.

$$-\frac{2}{3}x=-\frac{8}{5}-5$$

Convert 5 to fraction \frac{25}{5}.

$$-\frac{2}{3}x=-\frac{8}{5}-\frac{25}{5}$$

Since -\frac{8}{5} and \frac{25}{5} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{2}{3}x=\frac{-8-25}{5}$$

Subtract 25 from -8 to get -33.

$$-\frac{2}{3}x=-\frac{33}{5}$$

Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.

$$x=-\frac{33}{5}\left(-\frac{3}{2}\right)$$

Multiply -\frac{33}{5} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-33\left(-3\right)}{5\times 2}$$

Do the multiplications in the fraction \frac{-33\left(-3\right)}{5\times 2}.

$$x=\frac{99}{10}$$