Solve -18a^2b^2/5cd:6ab/5c^2d^4

$$\frac { - 18 a ^ { 2 } b ^ { 2 } } { 5 c d } : \frac { 6 a b } { 5 c ^ { 2 } d ^ { 4 } }$$

Evaluate

$$-3abcd^{3}$$

Solution Steps

Divide \frac{-18a^{2}b^{2}}{5cd} by \frac{6ab}{5c^{2}d^{4}} by multiplying \frac{-18a^{2}b^{2}}{5cd} by the reciprocal of \frac{6ab}{5c^{2}d^{4}}.

$$\frac{-18a^{2}b^{2}\times 5c^{2}d^{4}}{5cd\times 6ab}$$

Cancel out 5\times 6abcd in both numerator and denominator.

$$-3abcd^{3}$$

Differentiate w.r.t. d

$$-9abcd^{2}$$