Solve -(2^5*2^6)(2^0)/2^3

$$\frac { - ( 2 ^ { 5 } \cdot 2 ^ { 6 } ) ( 2 ^ { 0 } ) } { 2 ^ { 3 } }$$

Evaluate

$$-256$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 5 and 6 to get 11.

$$\frac{\left(-2^{11}\right)\times 2^{0}}{2^{3}}$$

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$\frac{-2^{11}}{2^{3}}$$

Calculate 2 to the power of 11 and get 2048.

$$\frac{-2048}{2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{-2048}{8}$$

Divide -2048 by 8 to get -256.

$$-256$$

Factor

$$-256$$