Solve for n
n=63
n=-64
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\left(n+1\right)n=2016\times 2
Multiply both sides by 2.
n^{2}+n=2016\times 2
Use the distributive property to multiply n+1 by n.
n^{2}+n=4032
Multiply 2016 and 2 to get 4032.
n^{2}+n-4032=0
Subtract 4032 from both sides.
n=\frac{-1±\sqrt{1^{2}-4\left(-4032\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 1 for b, and -4032 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-1±\sqrt{1-4\left(-4032\right)}}{2}
Square 1.
n=\frac{-1±\sqrt{1+16128}}{2}
Multiply -4 times -4032.
n=\frac{-1±\sqrt{16129}}{2}
Add 1 to 16128.
n=\frac{-1±127}{2}
Take the square root of 16129.
n=\frac{126}{2}
Now solve the equation n=\frac{-1±127}{2} when ± is plus. Add -1 to 127.
n=63
Divide 126 by 2.
n=-\frac{128}{2}
Now solve the equation n=\frac{-1±127}{2} when ± is minus. Subtract 127 from -1.
n=-64
Divide -128 by 2.
n=63 n=-64
The equation is now solved.
\left(n+1\right)n=2016\times 2
Multiply both sides by 2.
n^{2}+n=2016\times 2
Use the distributive property to multiply n+1 by n.
n^{2}+n=4032
Multiply 2016 and 2 to get 4032.
n^{2}+n+\left(\frac{1}{2}\right)^{2}=4032+\left(\frac{1}{2}\right)^{2}
Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2}. Then add the square of \frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}+n+\frac{1}{4}=4032+\frac{1}{4}
Square \frac{1}{2} by squaring both the numerator and the denominator of the fraction.
n^{2}+n+\frac{1}{4}=\frac{16129}{4}
Add 4032 to \frac{1}{4}.
\left(n+\frac{1}{2}\right)^{2}=\frac{16129}{4}
Factor n^{2}+n+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n+\frac{1}{2}\right)^{2}}=\sqrt{\frac{16129}{4}}
Take the square root of both sides of the equation.
n+\frac{1}{2}=\frac{127}{2} n+\frac{1}{2}=-\frac{127}{2}
Simplify.
n=63 n=-64
Subtract \frac{1}{2} from both sides of the equation.
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