Solve (658)^3-(328)^3/(658)^2+658*328+(328)^2

$$\frac { ( 658 ) ^ { 3 } - ( 328 ) ^ { 3 } } { ( 658 ) ^ { 2 } + 658 \times 328 + ( 328 ) ^ { 2 } }$$

Evaluate

$$330$$

Solution Steps

Calculate 658 to the power of 3 and get 284890312.

$$\frac{284890312-328^{3}}{658^{2}+658\times 328+328^{2}}$$

Calculate 328 to the power of 3 and get 35287552.

$$\frac{284890312-35287552}{658^{2}+658\times 328+328^{2}}$$

Subtract 35287552 from 284890312 to get 249602760.

$$\frac{249602760}{658^{2}+658\times 328+328^{2}}$$

Calculate 658 to the power of 2 and get 432964.

$$\frac{249602760}{432964+658\times 328+328^{2}}$$

Multiply 658 and 328 to get 215824.

$$\frac{249602760}{432964+215824+328^{2}}$$

Add 432964 and 215824 to get 648788.

$$\frac{249602760}{648788+328^{2}}$$

Calculate 328 to the power of 2 and get 107584.

$$\frac{249602760}{648788+107584}$$

Add 648788 and 107584 to get 756372.

$$\frac{249602760}{756372}$$

Divide 249602760 by 756372 to get 330.

$$330$$

Factor

$$2\times 3\times 5\times 11$$