Solve (5*3)-545+(5*3-5*33)/6

$$\frac { ( 5 \cdot 3 ) - 545 + ( 5 \cdot 3 - 5 \cdot 33 ) } { 6 }$$

Evaluate

$$-\frac{340}{3}\approx -113.333333333$$

Solution Steps

Multiply 5 and 3 to get 15.

$$\frac{15-545+5\times 3-5\times 33}{6}$$

Subtract 545 from 15 to get -530.

$$\frac{-530+5\times 3-5\times 33}{6}$$

Multiply 5 and 3 to get 15.

$$\frac{-530+15-5\times 33}{6}$$

Multiply 5 and 33 to get 165.

$$\frac{-530+15-165}{6}$$

Subtract 165 from 15 to get -150.

$$\frac{-530-150}{6}$$

Subtract 150 from -530 to get -680.

$$\frac{-680}{6}$$

Reduce the fraction \frac{-680}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{340}{3}$$

Factor

$$-\frac{340}{3} = -113\frac{1}{3} = -113.33333333333333$$