Solve (5*3^3-11*-3)*3^2/(-3^2+2^3)+7

$$\frac { ( 5 \cdot 3 ^ { 3 } - 11 \cdot - 3 ) \cdot 3 ^ { 2 } } { ( - 3 ^ { 2 } + 2 ^ { 3 } ) + 7 }$$

Evaluate

$$252$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$\frac{\left(5\times 27-11\left(-3\right)\right)\times 3^{2}}{-3^{2}+2^{3}+7}$$

Multiply 5 and 27 to get 135.

$$\frac{\left(135-11\left(-3\right)\right)\times 3^{2}}{-3^{2}+2^{3}+7}$$

Multiply 11 and -3 to get -33.

$$\frac{\left(135-\left(-33\right)\right)\times 3^{2}}{-3^{2}+2^{3}+7}$$

The opposite of -33 is 33.

$$\frac{\left(135+33\right)\times 3^{2}}{-3^{2}+2^{3}+7}$$

Add 135 and 33 to get 168.

$$\frac{168\times 3^{2}}{-3^{2}+2^{3}+7}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{168\times 9}{-3^{2}+2^{3}+7}$$

Multiply 168 and 9 to get 1512.

$$\frac{1512}{-3^{2}+2^{3}+7}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{1512}{-9+2^{3}+7}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{1512}{-9+8+7}$$

Add -9 and 8 to get -1.

$$\frac{1512}{-1+7}$$

Add -1 and 7 to get 6.

$$\frac{1512}{6}$$

Divide 1512 by 6 to get 252.

$$252$$

Factor

$$2^{2}\times 3^{2}\times 7$$