Solve (4-3)^2/2*3*4-(4-3)^2

$$\frac { ( 4 - 3 ) ^ { 2 } } { 2 \times 3 \times 4 - ( 4 - 3 ) ^ { 2 } }$$

Evaluate

$$\frac{1}{23}\approx 0.043478261$$

Solution Steps

Subtract 3 from 4 to get 1.

$$\frac{1^{2}}{2\times 3\times 4-\left(4-3\right)^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{1}{2\times 3\times 4-\left(4-3\right)^{2}}$$

Multiply 2 and 3 to get 6.

$$\frac{1}{6\times 4-\left(4-3\right)^{2}}$$

Multiply 6 and 4 to get 24.

$$\frac{1}{24-\left(4-3\right)^{2}}$$

Subtract 3 from 4 to get 1.

$$\frac{1}{24-1^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{1}{24-1}$$

Subtract 1 from 24 to get 23.

$$\frac{1}{23}$$

Factor

$$\frac{1}{23} = 0.043478260869565216$$