Solve frac{(3*2^3-2^4):sqrt[3]{8}}{21}=2/a

$$\frac { ( 3 \cdot 2 ^ { 3 } - 2 ^ { 4 } ) : \sqrt[ 3 ] { 8 } } { 21 } = \frac { 2 } { a }$$

Solve for a

$$a = \frac{21}{2} = 10\frac{1}{2} = 10.5$$

Steps for Solving Linear Equation

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 21a, the least common multiple of 21,a.

$$a\times \frac{3\times 2^{3}-2^{4}}{\sqrt[3]{8}}=21\times 2$$

Calculate 2 to the power of 3 and get 8.

$$a\times \frac{3\times 8-2^{4}}{\sqrt[3]{8}}=21\times 2$$

Multiply 3 and 8 to get 24.

$$a\times \frac{24-2^{4}}{\sqrt[3]{8}}=21\times 2$$

Calculate 2 to the power of 4 and get 16.

$$a\times \frac{24-16}{\sqrt[3]{8}}=21\times 2$$

Subtract 16 from 24 to get 8.

$$a\times \frac{8}{\sqrt[3]{8}}=21\times 2$$

Calculate \sqrt[3]{8} and get 2.

$$a\times \frac{8}{2}=21\times 2$$

Divide 8 by 2 to get 4.

$$a\times 4=21\times 2$$

Multiply 21 and 2 to get 42.

$$a\times 4=42$$

Divide both sides by 4.

$$a=\frac{42}{4}$$

Reduce the fraction \frac{42}{4} to lowest terms by extracting and canceling out 2.

$$a=\frac{21}{2}$$