Solve frac{(2x^{2}+8+x^3-x+2)(x^2+8)}{(x^4+x^3-6)}

$$\frac { ( 2 x ^ { 2 } + 8 + x ^ { 3 } - x + 2 ) ( x ^ { 2 } + 8 ) } { ( x ^ { 4 } + x ^ { 3 } - 6 ) }$$

Evaluate

$$\frac{\left(x^{2}+8\right)\left(x^{3}+2x^{2}-x+10\right)}{x^{4}+x^{3}-6}$$

Short Solution Steps

Add 8 and 2 to get 10.

$$\frac{\left(2x^{2}+10+x^{3}-x\right)\left(x^{2}+8\right)}{x^{4}+x^{3}-6}$$

Use the distributive property to multiply 2x^{2}+10+x^{3}-x by x^{2}+8 and combine like terms.

$$\frac{2x^{4}+26x^{2}+80+x^{5}+7x^{3}-8x}{x^{4}+x^{3}-6}$$

Expand

$$\frac{x^{5}+2x^{4}+7x^{3}+26x^{2}-8x+80}{x^{4}+x^{3}-6}$$

Short Solution Steps

Add 8 and 2 to get 10.

$$\frac{\left(2x^{2}+10+x^{3}-x\right)\left(x^{2}+8\right)}{x^{4}+x^{3}-6}$$

Use the distributive property to multiply 2x^{2}+10+x^{3}-x by x^{2}+8 and combine like terms.

$$\frac{2x^{4}+26x^{2}+80+x^{5}+7x^{3}-8x}{x^{4}+x^{3}-6}$$