Solve (2^5*2^-6*2)^2/2^3

$$\frac { ( 2 ^ { 5 } \cdot 2 ^ { - 6 } \cdot 2 ) ^ { 2 } } { 2 ^ { 3 } }$$

Evaluate

$$\frac{1}{8}=0.125$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 5 and -6 to get -1.

$$\frac{\left(2^{-1}\times 2\right)^{2}}{2^{3}}$$

Multiply 2^{-1} and 2 to get 1.

$$\frac{1^{2}}{2^{3}}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{1}{2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{1}{8}$$

Factor

$$\frac{1}{2 ^ {3}} = 0.125$$