Solve frac{(2^{3}*2^4*2^-7)^5}{2^-3}=

$$\frac { ( 2 ^ { 3 } \cdot 2 ^ { 4 } \cdot 2 ^ { - 7 } ) ^ { 5 } } { 2 ^ { - 3 } } =$$

Evaluate

$$8$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 4 to get 7.

$$\frac{\left(2^{7}\times 2^{-7}\right)^{5}}{2^{-3}}$$

Multiply 2^{7} and 2^{-7} to get 1.

$$\frac{1^{5}}{2^{-3}}$$

Calculate 1 to the power of 5 and get 1.

$$\frac{1}{2^{-3}}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\frac{1}{\frac{1}{8}}$$

Divide 1 by \frac{1}{8} by multiplying 1 by the reciprocal of \frac{1}{8}.

$$1\times 8$$

Multiply 1 and 8 to get 8.

$$8$$

Factor

$$2^{3}$$