Solve (-4)(-3)-[5-(+27)div(-3)]/(-3)^2-6*4-1=

$$\frac { ( - 4 ) ( - 3 ) - [ 5 - ( + 27 ) \div ( - 3 ) ] } { ( - 3 ) ^ { 2 } - 6 \times 4 - 1 } =$$

Evaluate

$$\frac{1}{8}=0.125$$

Solution Steps

Multiply -4 and -3 to get 12.

$$\frac{12-\left(5-\frac{27}{-3}\right)}{\left(-3\right)^{2}-6\times 4-1}$$

Divide 27 by -3 to get -9.

$$\frac{12-\left(5-\left(-9\right)\right)}{\left(-3\right)^{2}-6\times 4-1}$$

The opposite of -9 is 9.

$$\frac{12-\left(5+9\right)}{\left(-3\right)^{2}-6\times 4-1}$$

Add 5 and 9 to get 14.

$$\frac{12-14}{\left(-3\right)^{2}-6\times 4-1}$$

Subtract 14 from 12 to get -2.

$$\frac{-2}{\left(-3\right)^{2}-6\times 4-1}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{-2}{9-6\times 4-1}$$

Multiply 6 and 4 to get 24.

$$\frac{-2}{9-24-1}$$

Subtract 24 from 9 to get -15.

$$\frac{-2}{-15-1}$$

Subtract 1 from -15 to get -16.

$$\frac{-2}{-16}$$

Reduce the fraction \frac{-2}{-16} to lowest terms by extracting and canceling out -2.

$$\frac{1}{8}$$

Factor

$$\frac{1}{2 ^ {3}} = 0.125$$