Solve (2/3)/6^-1+7^0

$$\frac { ( \frac { 2 } { 3 } ) } { 6 ^ { - 1 } + 7 ^ { 0 } }$$

Evaluate

$$\frac{4}{7}\approx 0.571428571$$

Solution Steps

Calculate 6 to the power of -1 and get \frac{1}{6}.

$$\frac{\frac{2}{3}}{\frac{1}{6}+7^{0}}$$

Calculate 7 to the power of 0 and get 1.

$$\frac{\frac{2}{3}}{\frac{1}{6}+1}$$

Add \frac{1}{6} and 1 to get \frac{7}{6}.

$$\frac{\frac{2}{3}}{\frac{7}{6}}$$

Divide \frac{2}{3} by \frac{7}{6} by multiplying \frac{2}{3} by the reciprocal of \frac{7}{6}.

$$\frac{2}{3}\times \frac{6}{7}$$

Multiply \frac{2}{3} and \frac{6}{7} to get \frac{4}{7}.

$$\frac{4}{7}$$

Factor

$$\frac{2 ^ {2}}{7} = 0.5714285714285714$$