Solve |2^2-16:2|/-3^2+5=

$$\frac { | 2 ^ { 2 } - 16 : 2 | } { - 3 ^ { 2 } + 5 } =$$

Evaluate

$$-1$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{|4-\frac{16}{2}|}{-3^{2}+5}$$

Divide 16 by 2 to get 8.

$$\frac{|4-8|}{-3^{2}+5}$$

Subtract 8 from 4 to get -4.

$$\frac{|-4|}{-3^{2}+5}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$\frac{4}{-3^{2}+5}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{4}{-9+5}$$

Add -9 and 5 to get -4.

$$\frac{4}{-4}$$

Divide 4 by -4 to get -1.

$$-1$$

Factor

$$-1$$