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\frac{\sqrt{7}\left(\sqrt{10}+\sqrt{2}\right)}{\left(\sqrt{10}-\sqrt{2}\right)\left(\sqrt{10}+\sqrt{2}\right)}
Rationalize the denominator of \frac{\sqrt{7}}{\sqrt{10}-\sqrt{2}} by multiplying numerator and denominator by \sqrt{10}+\sqrt{2}.
\frac{\sqrt{7}\left(\sqrt{10}+\sqrt{2}\right)}{\left(\sqrt{10}\right)^{2}-\left(\sqrt{2}\right)^{2}}
Consider \left(\sqrt{10}-\sqrt{2}\right)\left(\sqrt{10}+\sqrt{2}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\sqrt{7}\left(\sqrt{10}+\sqrt{2}\right)}{10-2}
Square \sqrt{10}. Square \sqrt{2}.
\frac{\sqrt{7}\left(\sqrt{10}+\sqrt{2}\right)}{8}
Subtract 2 from 10 to get 8.
\frac{\sqrt{7}\sqrt{10}+\sqrt{7}\sqrt{2}}{8}
Use the distributive property to multiply \sqrt{7} by \sqrt{10}+\sqrt{2}.
\frac{\sqrt{70}+\sqrt{7}\sqrt{2}}{8}
To multiply \sqrt{7} and \sqrt{10}, multiply the numbers under the square root.
\frac{\sqrt{70}+\sqrt{14}}{8}
To multiply \sqrt{7} and \sqrt{2}, multiply the numbers under the square root.