Solve frac{sqrt{64}-sqrt[3]{-8}+3sqrt{4}}{2}

$$\frac { \sqrt { 64 } - \sqrt[ 3 ] { - 8 } + 3 \sqrt { 4 } } { 2 }$$

Evaluate

$$8$$

Solution Steps

Calculate the square root of 64 and get 8.

$$\frac{8-\sqrt[3]{-8}+3\sqrt{4}}{2}$$

Calculate \sqrt[3]{-8} and get -2.

$$\frac{8-\left(-2\right)+3\sqrt{4}}{2}$$

The opposite of -2 is 2.

$$\frac{8+2+3\sqrt{4}}{2}$$

Add 8 and 2 to get 10.

$$\frac{10+3\sqrt{4}}{2}$$

Calculate the square root of 4 and get 2.

$$\frac{10+3\times 2}{2}$$

Multiply 3 and 2 to get 6.

$$\frac{10+6}{2}$$

Add 10 and 6 to get 16.

$$\frac{16}{2}$$

Divide 16 by 2 to get 8.

$$8$$

Factor

$$2^{3}$$