Solve frac{sqrt{64}}{2}+sqrt[3]{64}-sqrt{(-6)^2}=

$$\frac { \sqrt { 64 } } { 2 } + \sqrt[ 3 ] { 64 } - \sqrt { ( - 6 ) ^ { 2 } } =$$

Evaluate

$$2$$

Solution Steps

Calculate the square root of 64 and get 8.

$$\frac{8}{2}+\sqrt[3]{64}-\sqrt{\left(-6\right)^{2}}$$

Divide 8 by 2 to get 4.

$$4+\sqrt[3]{64}-\sqrt{\left(-6\right)^{2}}$$

Calculate \sqrt[3]{64} and get 4.

$$4+4-\sqrt{\left(-6\right)^{2}}$$

Add 4 and 4 to get 8.

$$8-\sqrt{\left(-6\right)^{2}}$$

Calculate -6 to the power of 2 and get 36.

$$8-\sqrt{36}$$

Calculate the square root of 36 and get 6.

$$8-6$$

Subtract 6 from 8 to get 2.

$$2$$

Factor

$$2$$