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\frac{\sqrt{5}+2\sqrt{2}}{\sqrt{2}}-\left(\sqrt{3}\right)^{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{\left(\sqrt{5}+2\sqrt{2}\right)\sqrt{2}}{\left(\sqrt{2}\right)^{2}}-\left(\sqrt{3}\right)^{2}
Rationalize the denominator of \frac{\sqrt{5}+2\sqrt{2}}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\left(\sqrt{5}+2\sqrt{2}\right)\sqrt{2}}{2}-\left(\sqrt{3}\right)^{2}
The square of \sqrt{2} is 2.
\frac{\left(\sqrt{5}+2\sqrt{2}\right)\sqrt{2}}{2}-3
The square of \sqrt{3} is 3.
\frac{\left(\sqrt{5}+2\sqrt{2}\right)\sqrt{2}}{2}-\frac{3\times 2}{2}
To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2}{2}.
\frac{\left(\sqrt{5}+2\sqrt{2}\right)\sqrt{2}-3\times 2}{2}
Since \frac{\left(\sqrt{5}+2\sqrt{2}\right)\sqrt{2}}{2} and \frac{3\times 2}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{\sqrt{10}+4-6}{2}
Do the multiplications in \left(\sqrt{5}+2\sqrt{2}\right)\sqrt{2}-3\times 2.
\frac{\sqrt{10}-2}{2}
Do the calculations in \sqrt{10}+4-6.