Solve frac{sqrt{3}BC+10*1.732}{3}=BC

$$\frac { \sqrt { 3 } B C + 10 \times 1.732 } { 3 } = B C$$

Solve for B

$$B=\frac{433\sqrt{3}\left(\sqrt{3}+1\right)}{150C}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$\sqrt{3}BC+10\times 1.732=3BC$$

Multiply 10 and 1.732 to get 17.32.

$$\sqrt{3}BC+17.32=3BC$$

Subtract 3BC from both sides.

$$\sqrt{3}BC+17.32-3BC=0$$

Subtract 17.32 from both sides. Anything subtracted from zero gives its negation.

$$\sqrt{3}BC-3BC=-17.32$$

Combine all terms containing B.

$$\left(\sqrt{3}C-3C\right)B=-17.32$$

Divide both sides by \sqrt{3}C-3C.

$$\frac{\left(\sqrt{3}C-3C\right)B}{\sqrt{3}C-3C}=-\frac{17.32}{\sqrt{3}C-3C}$$

Dividing by \sqrt{3}C-3C undoes the multiplication by \sqrt{3}C-3C.

$$B=-\frac{17.32}{\sqrt{3}C-3C}$$

Divide -17.32 by \sqrt{3}C-3C.

$$B=\frac{433\left(\sqrt{3}+3\right)}{150C}$$

Solve for C

$$C=\frac{433\sqrt{3}\left(\sqrt{3}+1\right)}{150B}$$

$$B\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$\sqrt{3}BC+10\times 1.732=3BC$$

Multiply 10 and 1.732 to get 17.32.

$$\sqrt{3}BC+17.32=3BC$$

Subtract 3BC from both sides.

$$\sqrt{3}BC+17.32-3BC=0$$

Subtract 17.32 from both sides. Anything subtracted from zero gives its negation.

$$\sqrt{3}BC-3BC=-17.32$$

Combine all terms containing C.

$$\left(\sqrt{3}B-3B\right)C=-17.32$$

Divide both sides by \sqrt{3}B-3B.

$$\frac{\left(\sqrt{3}B-3B\right)C}{\sqrt{3}B-3B}=-\frac{17.32}{\sqrt{3}B-3B}$$

Dividing by \sqrt{3}B-3B undoes the multiplication by \sqrt{3}B-3B.

$$C=-\frac{17.32}{\sqrt{3}B-3B}$$

Divide -17.32 by \sqrt{3}B-3B.

$$C=\frac{433\left(\sqrt{3}+3\right)}{150B}$$