Solve frac{sqrt{3}}{6}x+sqrt{3}

$$\frac { \sqrt { 3 } } { 6 } x + \sqrt { 3 }$$

Evaluate

$$\frac{\sqrt{3}\left(x+6\right)}{6}$$

Short Solution Steps

Express \frac{\sqrt{3}}{6}x as a single fraction.

$$\frac{\sqrt{3}x}{6}+\sqrt{3}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply \sqrt{3} times \frac{6}{6}.

$$\frac{\sqrt{3}x}{6}+\frac{6\sqrt{3}}{6}$$

Since \frac{\sqrt{3}x}{6} and \frac{6\sqrt{3}}{6} have the same denominator, add them by adding their numerators.

$$\frac{\sqrt{3}x+6\sqrt{3}}{6}$$

Factor

$$\frac{\sqrt{3}\left(x+6\right)}{6}$$

Solution Steps

Factor out \frac{1}{6}.

$$\frac{\sqrt{3}x+6\sqrt{3}}{6}$$

Consider \sqrt{3}x+6\sqrt{3}. Factor out \sqrt{3}.

$$\sqrt{3}\left(x+6\right)$$

Rewrite the complete factored expression.

$$\frac{\sqrt{3}\left(x+6\right)}{6}$$