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\frac{\sqrt{3}}{2^{2}-\left(\sqrt{3}\right)^{2}}
Consider \left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\sqrt{3}}{4-\left(\sqrt{3}\right)^{2}}
Calculate 2 to the power of 2 and get 4.
\frac{\sqrt{3}}{4-3}
The square of \sqrt{3} is 3.
\frac{\sqrt{3}}{1}
Subtract 3 from 4 to get 1.
\sqrt{3}
Anything divided by one gives itself.