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\frac{\sqrt{3}+\frac{\sqrt{3}}{\left(\sqrt{3}\right)^{2}}}{\sqrt{3}-\frac{1}{\sqrt{3}}}
Rationalize the denominator of \frac{1}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\sqrt{3}+\frac{\sqrt{3}}{3}}{\sqrt{3}-\frac{1}{\sqrt{3}}}
The square of \sqrt{3} is 3.
\frac{\frac{4}{3}\sqrt{3}}{\sqrt{3}-\frac{1}{\sqrt{3}}}
Combine \sqrt{3} and \frac{\sqrt{3}}{3} to get \frac{4}{3}\sqrt{3}.
\frac{\frac{4}{3}\sqrt{3}}{\sqrt{3}-\frac{\sqrt{3}}{\left(\sqrt{3}\right)^{2}}}
Rationalize the denominator of \frac{1}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\frac{4}{3}\sqrt{3}}{\sqrt{3}-\frac{\sqrt{3}}{3}}
The square of \sqrt{3} is 3.
\frac{\frac{4}{3}\sqrt{3}}{\frac{2}{3}\sqrt{3}}
Combine \sqrt{3} and -\frac{\sqrt{3}}{3} to get \frac{2}{3}\sqrt{3}.
\frac{\frac{4}{3}}{\frac{2}{3}}
Cancel out \sqrt{3} in both numerator and denominator.
\frac{4}{3}\times \frac{3}{2}
Divide \frac{4}{3} by \frac{2}{3} by multiplying \frac{4}{3} by the reciprocal of \frac{2}{3}.
\frac{4\times 3}{3\times 2}
Multiply \frac{4}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
\frac{4}{2}
Cancel out 3 in both numerator and denominator.
2
Divide 4 by 2 to get 2.