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Topics
Pre-Algebra
Mean
Mode
Greatest Common Factor
Least Common Multiple
Order of Operations
Fractions
Mixed Fractions
Prime Factorization
Exponents
Radicals
Algebra
Combine Like Terms
Solve for a Variable
Factor
Expand
Evaluate Fractions
Linear Equations
Quadratic Equations
Inequalities
Systems of Equations
Matrices
Trigonometry
Simplify
Evaluate
Graphs
Solve Equations
Calculus
Derivatives
Integrals
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Evaluate
\sqrt{\frac{2}{x}}
Differentiate w.r.t. x
-\frac{\sqrt{2}}{2x^{\frac{3}{2}}}
Graph
Quiz
Algebra
5 problems similar to:
\frac { \sqrt { 2 x } } { x }
Similar Problems from Web Search
How do you simplify \displaystyle\sqrt{{\frac{{{2}{x}}}{{{9}{x}}}}} ?
https://socratic.org/questions/how-do-you-simplify-sqrt-2x-9x
\displaystyle\sqrt{{\frac{{{2}{x}}}{{{9}{x}}}}}=\frac{\sqrt{{{2}}}}{{3}} excluding \displaystyle{x}={0} Explanation: For any positive Real numbers \displaystyle{a},{b} : \displaystyle\sqrt{{\frac{{a}}{{b}}}}=\frac{\sqrt{{{a}}}}{\sqrt{{{b}}}} ...
How do you rationalize the denominator and simplify \displaystyle\frac{{6}}{{\sqrt{{{2}{x}}}}} ?
https://socratic.org/questions/how-do-you-rationalize-the-denominator-and-simplify-6-sqrt-2x
\displaystyle\frac{{{3}\sqrt{{{2}{x}}}}}{{x}} Explanation: \displaystyle\frac{{6}}{{\sqrt{{{2}{x}}}}} \displaystyle\frac{{6}}{{\sqrt{{{2}{x}}}}}\cdot{\left[\frac{{\cancel{-}\sqrt{{{2}{x}}}}}{{\cancel{{-}}\sqrt{{{2}{x}}}}}\right]} ...
How do you solve \displaystyle\frac{{x}}{{2}}=\sqrt{{{x}-{1}}} ?
https://socratic.org/questions/how-do-you-solve-x-2-sqrt-x-1
\displaystyle{x}={2} Explanation: First, start by taking a look at the equation \displaystyle\sqrt{{{x}-{1}}}=\frac{{x}}{{2}} Right from the start, you need \displaystyle{x} to be ...
How do you solve \displaystyle\frac{\sqrt{{{2}{x}}}}{{5}}={6} ?
https://socratic.org/questions/how-do-you-solve-sqrt-2x-5-6
450 Explanation: \displaystyle\frac{\sqrt{{{2}{x}}}}{{5}}={6} \displaystyle\sqrt{{{2}{x}}}={30} \displaystyle{2}{x}={30}^{{2}} \displaystyle{2}{x}={900} \displaystyle{x}={450}
Integral of \sqrt{\frac{x}{x+1}}
https://math.stackexchange.com/q/2588817
If you consider y=\sqrt{x(x+1)}, then y^2=x^2+x=(x+1/2)^2-1/4 or \left(x+\frac{1}{2}\right)^{\!2}-y^2=\frac{1}{4} which suggests making the substitution x+\frac{1}{2}=\frac{1}{2}\cosh t \qquad y=\frac{1}{2}\sinh t \qquad dx=\frac{1}{2}\sinh t\,dt ...
What is the limit of \displaystyle\frac{{\sqrt{{x}}}}{{{x}+{4}}} as x approaches infinity?
https://socratic.org/questions/what-is-the-limit-of-sqrt-x-x-4-as-x-approaches-infinity
0 Explanation: \displaystyle\lim\to infinity of the ratio of \displaystyle\frac{{x}^{{m}}}{{x}^{{n}}} is 0 or infinity, according as, when m < or < n. . Divide by \displaystyle\sqrt{{x}} ...
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
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