Solve frac{sqrt{2x}}{4}+3=5

$$\frac { \sqrt { 2 x } } { 4 } + 3 = 5$$

Solve for x

$$x=32$$

Steps for Solving Radical Equations

Subtract 3 from both sides of the equation.

$$\frac{1}{4}\sqrt{2x}+3-3=5-3$$

Subtracting 3 from itself leaves 0.

$$\frac{1}{4}\sqrt{2x}=5-3$$

Subtract 3 from 5.

$$\frac{1}{4}\sqrt{2x}=2$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}\sqrt{2x}}{\frac{1}{4}}=\frac{2}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$\sqrt{2x}=\frac{2}{\frac{1}{4}}$$

Divide 2 by \frac{1}{4} by multiplying 2 by the reciprocal of \frac{1}{4}.

$$\sqrt{2x}=8$$

Square both sides of the equation.

$$2x=64$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{64}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{64}{2}$$

Divide 64 by 2.

$$x=32$$