Evaluate
\frac{x-2}{x^{2}-8}
Expand
\frac{x-2}{x^{2}-8}
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\frac{\left(x+4\right)\left(x-2\right)}{\left(x^{2}-8\right)\left(x+4\right)}
Divide \frac{x+4}{x^{2}-8} by \frac{x+4}{x-2} by multiplying \frac{x+4}{x^{2}-8} by the reciprocal of \frac{x+4}{x-2}.
\frac{x-2}{x^{2}-8}
Cancel out x+4 in both numerator and denominator.
\frac{\left(x+4\right)\left(x-2\right)}{\left(x^{2}-8\right)\left(x+4\right)}
Divide \frac{x+4}{x^{2}-8} by \frac{x+4}{x-2} by multiplying \frac{x+4}{x^{2}-8} by the reciprocal of \frac{x+4}{x-2}.
\frac{x-2}{x^{2}-8}
Cancel out x+4 in both numerator and denominator.
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