Solve 7/3-1/2-frac{9{4}}-1=

$$\frac { \frac { 7 } { 3 } - 1 } { 2 - \frac { 9 } { 4 } } - 1 =$$

Evaluate

$$-\frac{19}{3}\approx -6.333333333$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{7}{3}-\frac{3}{3}}{2-\frac{9}{4}}-1$$

Since \frac{7}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{7-3}{3}}{2-\frac{9}{4}}-1$$

Subtract 3 from 7 to get 4.

$$\frac{\frac{4}{3}}{2-\frac{9}{4}}-1$$

Convert 2 to fraction \frac{8}{4}.

$$\frac{\frac{4}{3}}{\frac{8}{4}-\frac{9}{4}}-1$$

Since \frac{8}{4} and \frac{9}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{4}{3}}{\frac{8-9}{4}}-1$$

Subtract 9 from 8 to get -1.

$$\frac{\frac{4}{3}}{-\frac{1}{4}}-1$$

Divide \frac{4}{3} by -\frac{1}{4} by multiplying \frac{4}{3} by the reciprocal of -\frac{1}{4}.

$$\frac{4}{3}\left(-4\right)-1$$

Express \frac{4}{3}\left(-4\right) as a single fraction.

$$\frac{4\left(-4\right)}{3}-1$$

Multiply 4 and -4 to get -16.

$$\frac{-16}{3}-1$$

Fraction \frac{-16}{3} can be rewritten as -\frac{16}{3} by extracting the negative sign.

$$-\frac{16}{3}-1$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{16}{3}-\frac{3}{3}$$

Since -\frac{16}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-16-3}{3}$$

Subtract 3 from -16 to get -19.

$$-\frac{19}{3}$$

Factor

$$-\frac{19}{3} = -6\frac{1}{3} = -6.333333333333333$$