Solve 3/8*(-3/4)/(frac{-3{4})}+5/8

$$\frac { \frac { 3 } { 8 } \times ( \frac { - 3 } { 4 } ) } { ( \frac { - 3 } { 4 } ) } + \frac { 5 } { 8 }$$

Evaluate

$$1$$

Solution Steps

Fraction \frac{-3}{4} can be rewritten as -\frac{3}{4} by extracting the negative sign.

$$\frac{\frac{3}{8}\left(-\frac{3}{4}\right)}{\frac{-3}{4}}+\frac{5}{8}$$

Multiply \frac{3}{8} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{3\left(-3\right)}{8\times 4}}{\frac{-3}{4}}+\frac{5}{8}$$

Do the multiplications in the fraction \frac{3\left(-3\right)}{8\times 4}.

$$\frac{\frac{-9}{32}}{\frac{-3}{4}}+\frac{5}{8}$$

Fraction \frac{-9}{32} can be rewritten as -\frac{9}{32} by extracting the negative sign.

$$\frac{-\frac{9}{32}}{\frac{-3}{4}}+\frac{5}{8}$$

Fraction \frac{-3}{4} can be rewritten as -\frac{3}{4} by extracting the negative sign.

$$\frac{-\frac{9}{32}}{-\frac{3}{4}}+\frac{5}{8}$$

Divide -\frac{9}{32} by -\frac{3}{4} by multiplying -\frac{9}{32} by the reciprocal of -\frac{3}{4}.

$$-\frac{9}{32}\left(-\frac{4}{3}\right)+\frac{5}{8}$$

Multiply -\frac{9}{32} times -\frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-9\left(-4\right)}{32\times 3}+\frac{5}{8}$$

Do the multiplications in the fraction \frac{-9\left(-4\right)}{32\times 3}.

$$\frac{36}{96}+\frac{5}{8}$$

Reduce the fraction \frac{36}{96} to lowest terms by extracting and canceling out 12.

$$\frac{3}{8}+\frac{5}{8}$$

Since \frac{3}{8} and \frac{5}{8} have the same denominator, add them by adding their numerators.

$$\frac{3+5}{8}$$

Add 3 and 5 to get 8.

$$\frac{8}{8}$$

Divide 8 by 8 to get 1.

$$1$$

Factor

$$1$$