Solve 2/5*1/4+(1/3)^0/sqrt[3]{1-frac{7{8}}}=

$$\frac { \frac { 2 } { 5 } \cdot \frac { 1 } { 4 } + ( \frac { 1 } { 3 } ) ^ { 0 } } { \sqrt[ 3 ] { 1 - \frac { 7 } { 8 } } } =$$

Evaluate

$$\frac{11}{5}=2.2$$

Solution Steps

Multiply \frac{2}{5} and \frac{1}{4} to get \frac{1}{10}.

$$\frac{\frac{1}{10}+\left(\frac{1}{3}\right)^{0}}{\sqrt[3]{1-\frac{7}{8}}}$$

Calculate \frac{1}{3} to the power of 0 and get 1.

$$\frac{\frac{1}{10}+1}{\sqrt[3]{1-\frac{7}{8}}}$$

Add \frac{1}{10} and 1 to get \frac{11}{10}.

$$\frac{\frac{11}{10}}{\sqrt[3]{1-\frac{7}{8}}}$$

Subtract \frac{7}{8} from 1 to get \frac{1}{8}.

$$\frac{\frac{11}{10}}{\sqrt[3]{\frac{1}{8}}}$$

Calculate \sqrt[3]{\frac{1}{8}} and get \frac{1}{2}.

$$\frac{\frac{11}{10}}{\frac{1}{2}}$$

Divide \frac{11}{10} by \frac{1}{2} by multiplying \frac{11}{10} by the reciprocal of \frac{1}{2}.

$$\frac{11}{10}\times 2$$

Multiply \frac{11}{10} and 2 to get \frac{11}{5}.

$$\frac{11}{5}$$

Factor

$$\frac{11}{5} = 2\frac{1}{5} = 2.2$$