Solve 10-9/10/frac{100-120{100}}=

$$\frac { \frac { 10 - 9 } { 10 } } { \frac { 100 - 120 } { 100 } } =$$

Evaluate

$$-\frac{1}{2}=-0.5$$

Solution Steps

Divide \frac{10-9}{10} by \frac{100-120}{100} by multiplying \frac{10-9}{10} by the reciprocal of \frac{100-120}{100}.

$$\frac{\left(10-9\right)\times 100}{10\left(100-120\right)}$$

Cancel out 10 in both numerator and denominator.

$$\frac{10\left(10-9\right)}{100-120}$$

Subtract 9 from 10 to get 1.

$$\frac{10\times 1}{100-120}$$

Multiply 10 and 1 to get 10.

$$\frac{10}{100-120}$$

Subtract 120 from 100 to get -20.

$$\frac{10}{-20}$$

Reduce the fraction \frac{10}{-20} to lowest terms by extracting and canceling out 10.

$$-\frac{1}{2}$$

Factor

$$-\frac{1}{2} = -0.5$$