Solve 1/6+49/36/2*frac{2{5}}

$$\frac { \frac { 1 } { 6 } + \frac { 49 } { 36 } } { 2 \times \frac { 2 } { 5 } }$$

Evaluate

$$\frac{275}{144}\approx 1.909722222$$

Solution Steps

Least common multiple of 6 and 36 is 36. Convert \frac{1}{6} and \frac{49}{36} to fractions with denominator 36.

$$\frac{\frac{6}{36}+\frac{49}{36}}{2\times \frac{2}{5}}$$

Since \frac{6}{36} and \frac{49}{36} have the same denominator, add them by adding their numerators.

$$\frac{\frac{6+49}{36}}{2\times \frac{2}{5}}$$

Add 6 and 49 to get 55.

$$\frac{\frac{55}{36}}{2\times \frac{2}{5}}$$

Express 2\times \frac{2}{5} as a single fraction.

$$\frac{\frac{55}{36}}{\frac{2\times 2}{5}}$$

Multiply 2 and 2 to get 4.

$$\frac{\frac{55}{36}}{\frac{4}{5}}$$

Divide \frac{55}{36} by \frac{4}{5} by multiplying \frac{55}{36} by the reciprocal of \frac{4}{5}.

$$\frac{55}{36}\times \frac{5}{4}$$

Multiply \frac{55}{36} times \frac{5}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{55\times 5}{36\times 4}$$

Do the multiplications in the fraction \frac{55\times 5}{36\times 4}.

$$\frac{275}{144}$$

Factor

$$\frac{5 ^ {2} \cdot 11}{2 ^ {4} \cdot 3 ^ {2}} = 1\frac{131}{144} = 1.9097222222222223$$