Solve 1/2+1/6/2-2(frac{7{3}-1)}div(-1/3-2)

$$\frac { \frac { 1 } { 2 } + \frac { 1 } { 6 } } { 2 - 2 ( \frac { 7 } { 3 } - 1 ) } \div ( - \frac { 1 } { 3 } - 2 )$$

Evaluate

$$\frac{3}{7}\approx 0.428571429$$

Solution Steps

Extract the negative sign in \frac{1}{2}+\frac{1}{6}.

$$\frac{\frac{-\left(2-2\left(\frac{7}{3}-1\right)\right)}{2-2\left(\frac{7}{3}-1\right)}}{-\frac{1}{3}-2}$$

Cancel out 2-2\left(\frac{7}{3}-1\right) in both numerator and denominator.

$$\frac{-1}{-\frac{1}{3}-2}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{-1}{-\frac{1}{3}-\frac{6}{3}}$$

Since -\frac{1}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1}{\frac{-1-6}{3}}$$

Subtract 6 from -1 to get -7.

$$\frac{-1}{-\frac{7}{3}}$$

Divide -1 by -\frac{7}{3} by multiplying -1 by the reciprocal of -\frac{7}{3}.

$$-\left(-\frac{3}{7}\right)$$

Multiply -1 and -\frac{3}{7} to get \frac{3}{7}.

$$\frac{3}{7}$$

Factor

$$\frac{3}{7} = 0.42857142857142855$$