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\frac{\mathrm{d}}{\mathrm{d}\gamma }(V)\delta \gamma +\frac{\mathrm{d}}{\mathrm{d}k}(V)\delta h=\delta V
Swap sides so that all variable terms are on the left hand side.
\frac{\mathrm{d}}{\mathrm{d}k}(V)\delta h=\delta V-\frac{\mathrm{d}}{\mathrm{d}\gamma }(V)\delta \gamma
Subtract \frac{\mathrm{d}}{\mathrm{d}\gamma }(V)\delta \gamma from both sides.
h\delta \frac{\mathrm{d}}{\mathrm{d}k}(V)=-\gamma \delta \frac{\mathrm{d}}{\mathrm{d}\gamma }(V)+V\delta
Reorder the terms.
0=V\delta
The equation is in standard form.
h\in
This is false for any h.