Solve Delta=4^2-4(4-10/3)

$$\Delta = 4 ^ { 2 } - 4 ( 4 - \frac { 10 } { 3 } )$$

Solve for Δ

$$\Delta =\frac{40}{3}\approx 13.333333333$$

Steps for Solving Linear Equation

Calculate 4 to the power of 2 and get 16.

$$\Delta =16-4\left(4-\frac{10}{3}\right)$$

Convert 4 to fraction \frac{12}{3}.

$$\Delta =16-4\left(\frac{12}{3}-\frac{10}{3}\right)$$

Since \frac{12}{3} and \frac{10}{3} have the same denominator, subtract them by subtracting their numerators.

$$\Delta =16-4\times \frac{12-10}{3}$$

Subtract 10 from 12 to get 2.

$$\Delta =16-4\times \frac{2}{3}$$

Express 4\times \frac{2}{3} as a single fraction.

$$\Delta =16-\frac{4\times 2}{3}$$

Multiply 4 and 2 to get 8.

$$\Delta =16-\frac{8}{3}$$

Convert 16 to fraction \frac{48}{3}.

$$\Delta =\frac{48}{3}-\frac{8}{3}$$

Since \frac{48}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\Delta =\frac{48-8}{3}$$

Subtract 8 from 48 to get 40.

$$\Delta =\frac{40}{3}$$

Assign Δ

$$\Delta ≔\frac{40}{3}$$