Solve {48[(16-12+8)div4+(24-18)div6]}div4=

$$\{ 48 [ ( 16 - 12 + 8 ) \div 4 + ( 24 - 18 ) \div 6 ] \} \div 4 =$$

Evaluate

$$48$$

Solution Steps

Subtract 12 from 16 to get 4.

$$\frac{48\left(\frac{4+8}{4}+\frac{24-18}{6}\right)}{4}$$

Add 4 and 8 to get 12.

$$\frac{48\left(\frac{12}{4}+\frac{24-18}{6}\right)}{4}$$

Divide 12 by 4 to get 3.

$$\frac{48\left(3+\frac{24-18}{6}\right)}{4}$$

Subtract 18 from 24 to get 6.

$$\frac{48\left(3+\frac{6}{6}\right)}{4}$$

Divide 6 by 6 to get 1.

$$\frac{48\left(3+1\right)}{4}$$

Add 3 and 1 to get 4.

$$\frac{48\times 4}{4}$$

Multiply 48 and 4 to get 192.

$$\frac{192}{4}$$

Divide 192 by 4 to get 48.

$$48$$

Factor

$$2^{4}\times 3$$