Solve {4-[3+2-(1-5-7)-2]+10}

$$\{ 4 - [ 3 + 2 - ( 1 - 5 - 7 ) - 2 ] + 10 \}$$

Evaluate

$$0$$

Solution Steps

Add 3 and 2 to get 5.

$$4-\left(5-\left(1-5-7\right)-2\right)+10$$

Subtract 5 from 1 to get -4.

$$4-\left(5-\left(-4-7\right)-2\right)+10$$

Subtract 7 from -4 to get -11.

$$4-\left(5-\left(-11\right)-2\right)+10$$

The opposite of -11 is 11.

$$4-\left(5+11-2\right)+10$$

Add 5 and 11 to get 16.

$$4-\left(16-2\right)+10$$

Subtract 2 from 16 to get 14.

$$4-14+10$$

Subtract 14 from 4 to get -10.

$$-10+10$$

Add -10 and 10 to get 0.

$$0$$

Factor

$$0$$