\{ 3 x + 2 y = 18
Solve for x
x=-\frac{2y}{3}+6
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3x=18-2y
Subtract 2y from both sides.
\frac{3x}{3}=\frac{18-2y}{3}
Divide both sides by 3.
x=\frac{18-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+6
Divide 18-2y by 3.
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