\{ 12 x + 2 y = 3
Solve for x
x=-\frac{y}{6}+\frac{1}{4}
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12x=3-2y
Subtract 2y from both sides.
\frac{12x}{12}=\frac{3-2y}{12}
Divide both sides by 12.
x=\frac{3-2y}{12}
Dividing by 12 undoes the multiplication by 12.
x=-\frac{y}{6}+\frac{1}{4}
Divide 3-2y by 12.
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