Solve {[(5^{0}+3*2^{3}):5]^2+6^2:4:3-12^2:9}:6*2*7^0-1

$$\{ [ ( 5 ^ { 0 } + 3 \cdot 2 ^ { 3 } ) : 5 ] ^ { 2 } + 6 ^ { 2 } : 4 : 3 - 12 ^ { 2 } : 9 \} : 6 \cdot 2 \cdot 7 ^ { 0 } - 1$$

Evaluate

$$3$$

Solution Steps

Calculate 5 to the power of 0 and get 1.

$$\frac{\left(\frac{1+3\times 2^{3}}{5}\right)^{2}+\frac{\frac{6^{2}}{4}}{3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Calculate 2 to the power of 3 and get 8.

$$\frac{\left(\frac{1+3\times 8}{5}\right)^{2}+\frac{\frac{6^{2}}{4}}{3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Multiply 3 and 8 to get 24.

$$\frac{\left(\frac{1+24}{5}\right)^{2}+\frac{\frac{6^{2}}{4}}{3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Add 1 and 24 to get 25.

$$\frac{\left(\frac{25}{5}\right)^{2}+\frac{\frac{6^{2}}{4}}{3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Divide 25 by 5 to get 5.

$$\frac{5^{2}+\frac{\frac{6^{2}}{4}}{3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Calculate 5 to the power of 2 and get 25.

$$\frac{25+\frac{\frac{6^{2}}{4}}{3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Express \frac{\frac{6^{2}}{4}}{3} as a single fraction.

$$\frac{25+\frac{6^{2}}{4\times 3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Calculate 6 to the power of 2 and get 36.

$$\frac{25+\frac{36}{4\times 3}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Multiply 4 and 3 to get 12.

$$\frac{25+\frac{36}{12}-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Divide 36 by 12 to get 3.

$$\frac{25+3-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Add 25 and 3 to get 28.

$$\frac{28-\frac{12^{2}}{9}}{6}\times 2\times 7^{0}-1$$

Calculate 12 to the power of 2 and get 144.

$$\frac{28-\frac{144}{9}}{6}\times 2\times 7^{0}-1$$

Divide 144 by 9 to get 16.

$$\frac{28-16}{6}\times 2\times 7^{0}-1$$

Subtract 16 from 28 to get 12.

$$\frac{12}{6}\times 2\times 7^{0}-1$$

Divide 12 by 6 to get 2.

$$2\times 2\times 7^{0}-1$$

Multiply 2 and 2 to get 4.

$$4\times 7^{0}-1$$

Calculate 7 to the power of 0 and get 1.

$$4\times 1-1$$

Multiply 4 and 1 to get 4.

$$4-1$$

Subtract 1 from 4 to get 3.

$$3$$

Factor

$$3$$