Solve [6*4(15div5)]+[2^2+(1*-5)]

$$[ 6 \cdot 4 ( 15 \div 5 ) ] + [ 2 ^ { 2 } + ( 1 \cdot - 5 ) ]$$

Evaluate

$$71$$

Solution Steps

Multiply 6 and 4 to get 24. Multiply 1 and -5 to get -5.

$$24\times \frac{15}{5}+2^{2}-5$$

Divide 15 by 5 to get 3.

$$24\times 3+2^{2}-5$$

Multiply 24 and 3 to get 72.

$$72+2^{2}-5$$

Calculate 2 to the power of 2 and get 4.

$$72+4-5$$

Add 72 and 4 to get 76.

$$76-5$$

Subtract 5 from 76 to get 71.

$$71$$

Factor

$$71$$