Solve [20*(5^2+6^6)-10*43]:58

$$[ 20 \cdot ( 5 ^ { 2 } + 6 ^ { 6 } ) - 10 \cdot 43 ] : 58$$

Evaluate

$$\frac{466595}{29}\approx 16089.482758621$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\frac{20\left(25+6^{6}\right)-10\times 43}{58}$$

Calculate 6 to the power of 6 and get 46656.

$$\frac{20\left(25+46656\right)-10\times 43}{58}$$

Add 25 and 46656 to get 46681.

$$\frac{20\times 46681-10\times 43}{58}$$

Multiply 20 and 46681 to get 933620.

$$\frac{933620-10\times 43}{58}$$

Multiply 10 and 43 to get 430.

$$\frac{933620-430}{58}$$

Subtract 430 from 933620 to get 933190.

$$\frac{933190}{58}$$

Reduce the fraction \frac{933190}{58} to lowest terms by extracting and canceling out 2.

$$\frac{466595}{29}$$

Factor

$$\frac{5 \cdot 93319}{29} = 16089\frac{14}{29} = 16089.48275862069$$